15x^2-2x-45=0

Solution for 15x^2-2x-45=0 equation:

15x^2-2x-45=0

a = 15; b = -2; c = -45;
Δ = b2-4ac
Δ = -22-4·15·(-45)
Δ = 2704
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2704}=52$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-52}{2*15}=\frac{-50}{30}
=-1+2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+52}{2*15}=\frac{54}{30}
=1+4/5
$